x^2+157x=2500

Solution for x^2+157x=2500 equation:

x^2+157x=2500

We move all terms to the left:

x^2+157x-(2500)=0

a = 1; b = 157; c = -2500;
Δ = b2-4ac
Δ = 1572-4·1·(-2500)
Δ = 34649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(157)-\sqrt{34649}}{2*1}=\frac{-157-\sqrt{34649}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(157)+\sqrt{34649}}{2*1}=\frac{-157+\sqrt{34649}}{2}
$